The Cost Of An Entry Level Yaris Is R220,000 And The Cost Of An Entry Level Etios Is R180,000. A Toyota Dealership Has R7 Million To Spend And Wants To Buy Equal Numbers Of The Entry Level Yaris And Etios. What Is The Largest Number Of Each Type Of Car That Can Be Ordered?
Answers
Answer:
Dealer can order 17 nos. of Yaris and Etios each
Explanation:
Given ,
Entry Level Yaris = Rs. 220,000
Entry Level Etios =Rs. 180,000
Amount with Toyota Dealer= Rs. 7 Million = Rs. 70,00,000
He wants to buy equal numbers of the entry level Yaris and Etios
Let n be the number of Yaris and Etios
n×220,000+ n×180,000= 7,000,000
n(220000+180000)= 7,000,000
n= 7,000,000/400,000
n= 17.5
Therefore,
The dealer can order maximum number of Yaris and Etios = 17 each
Largest number of each type of car that can be bought is 17 where car A cost R220000 and Car B cost approximately 81.818% of Car A and equal number of cars to be bought with R7 million
Given:
- price for Car A is R220 000,
- price for Car B is 81.818% of Car A.
- Explore Motors dealership has R7 million to spend
- wants to buy equal numbers of the entry levels of Car A and Car B
To Find:
- The largest number of each type of car that can be bought
Solution:
Assume that largest number of each type of car that can be bought is N
Step 1:
Find Cost of N cars of type A
220000N
Step 2:
Find Cost of N cars of type B
81.818% of 220000N
=( 81818/100000 )220000N
= 179999.6N
Step 3:
Find Total Cost of N cars of Each type
220000N + 179999.6N
= 3,99,999.6N
Step 4:
Total Cost should be less than or equal to 7 million = 7000000
Solve for N
3,99,999.6N ≤ 7000000
=> N ≤ 17.5
As car can be in integers Hence
Largest number of each type of car that can be bought is 17
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