Question

the cost of an one elephant is 5 rupees, the cost of one horse is 3 rupees and the cost of 1 goat is 5paisa . how can we find 100 animals in 100 rupees​

Answer 1

Step-by-step explanation:

Suppose that number of horses is x, number of elephants is y and number of camels is z.

prices are:

1 horse = Rs 1

1 elephnat = Rs 2

20 camels = Rs 1 means 1 camel = Rs 0.05.

we can form two equations:

total number of animals = 100

x+y+z = 100 …………….(1)

and total sum of money = 100

1x + 5y + 0.05z = 100 …………(2)

by equations (1) and (2)

-4y + 0.95z =0

.95z = 4y

z/y = 4/0.95

z/y = 80/19 (after simplification )

so if z(camels) = 80 and y(elephants) = 19

then horses,x = 100-y-z ( from equation 1)

x= 100–80–19

x=1

now

1 horse = Rs 1

19 elephnats = 19*5= Rs 95

80 camels = 80*0.05 = Rs 4

Note : The system of equations in this question has infinite solutions like x=50.5; y=9.5 and z=40, and x= -18; y= 38 and z=80, but in our question we need natural numbers values for x y and z, So only one solution satisfies our condition.

How do I purchase 100 animals in Rs 100? Where 1 horse is Rs 1, 1 elephant is Rs 5, and 4 camels are Rs 1?

1 cow costs 1 rupee. 1 buffalo costs 5 rupees. 20 goats cost 1 rupee. With 100 rupees, I bought a total of 100 animals of all three types. How many of each animal did I buy?

How do I buy 100 animals for 100 Rs if 1 goat is Rs 0.25, a horse is Rs 1, and an elephant is Rs 35?

1 cow costs 1 rupee. 5 buffalo costs 1 rupee. 1 goat cost 20 rupees. With 100 rupees, I bought a total of 100 animals of all three types. How many of each animal did I buy?

How do I purchase 100 animals for 100 rupees? Where 1 elephant costs 10 rupees, 1 camel costs .125, and 1 horse costs rupees 1?

consider , horse=h , elephant=e , camel=c

1 h = 1 Rs

1 e = 5 Rs

20 c = 1 Rs [1 c=0.05 Rs] .

80 c = 80 * 0.05=4 Rs.

19 e = 19 *5 = 95 Rs.

01 h = 1*1 = 1 Rs.

80 c+19 e+1 h=4 Rs+95 Rs+1 Rs

100 Animals=100 Rs