Math, asked by raj55353535, 19 days ago

the cost of carpeting a room at rs 90/m2 is rs 7200.if the length had been 5m less the cost would have been rs 3600.find the length and breadth of the room.

Answers

Answered by tennetiraj86
34

Step-by-step explanation:

Solution :-

Given that

The cost of carpeting a room at Rs.90 per 1 m² = Rs. 7200

Total area of the room

= Total cost / Cost per 1 m²

= 7200/90

= 80 m²

Are of the room = 80 m²

Let the length of the room be l m

Let the breadth of the room be b m

We know that

Area of a rectangle = length × breadth sq.units

Area of the room = lb

=> lb = 80 --------(1)

=> b = 80/l -------(2)

Given that

If the length had been 5 m less then the cost would have been = Rs. 3600

Area of the room = 3600/90 = 40 m²

According to the given problem

=> (l-5)b = 40

=> (l-5)(80/l) = 40 (from (1))

=> 80(l-5)/l = 40

=> 80(l-5) = 40l

=> 80 l - 400 = 40 l

=> 80 l -40 l = 400

=> 40 l = 400

=> l = 400/40

=> l = 10 m

Therefore, length = 10 m

From (2)

=> b = 80/10

=> b = 8 m

Therefore, breadth = 8 m

Answer:-

The length and breadth of the room are 10 m and 8 m

Check :-

Length = 10 m

Breadth = 8 m

Area = lb = 10×8 = 80 m²

Total cost of carpeting the room at Rs. 90/m²

=80×90 = Rs. 7200

and

If the length is reduced to 5 m then the new length = 10-5 = 5 m

Area = 5×8 = 40 m²

Total cost of carpeting the room at Rs. 90/m²

=40×90 = Rs. 3600

Verified the given relations in the given problem.

Used formulae:-

→Area of a rectangle is lb sq.units

  • l = length
  • b = breadth
Answered by krohit68654321
1

Step-by-step explanation:

Step-by-step explanation:

Solution :-

Given that

The cost of carpeting a room at Rs.90 per 1 m² = Rs. 7200

Total area of the room

= Total cost / Cost per 1 m²

= 7200/90

= 80 m²

Are of the room = 80 m²

Let the length of the room be l m

Let the breadth of the room be b m

We know that

Area of a rectangle = length × breadth sq.units

Area of the room = lb m²

=> lb = 80 --------(1)

=> b = 80/l -------(2)

Given that

If the length had been 5 m less then the cost would have been = Rs. 3600

Area of the room = 3600/90 = 40 m²

According to the given problem

=> (l-5)b = 40

=> (l-5)(80/l) = 40 (from (1))

=> 80(l-5)/l = 40

=> 80(l-5) = 40l

=> 80 l - 400 = 40 l

=> 80 l -40 l = 400

=> 40 l = 400

=> l = 400/40

=> l = 10 m

Therefore, length = 10 m

From (2)

=> b = 80/10

=> b = 8 m

Therefore, breadth = 8 m

Answer:-

The length and breadth of the room are 10 m and 8 m

Check :-

Length = 10 m

Breadth = 8 m

Area = lb = 10×8 = 80 m²

Total cost of carpeting the room at Rs. 90/m²

=80×90 = Rs. 7200

and

If the length is reduced to 5 m then the new length = 10-5 = 5 m

Area = 5×8 = 40 m²

Total cost of carpeting the room at Rs. 90/m²

=40×90 = Rs. 3600

Verified the given relations in the given problem.

Used formulae:-

→Area of a rectangle is lb sq.units

l = length

b = breadth

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