the cost of diamond (d) varies directly as the cube of its weight
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Ratio of diamond when broke is 3 : 2 : 1 : 1.
When the pieces were sold the merchant got 34600 less.
Concept used:
Using the concept simple ratio.
Calculation:
Let the weight of each piece of diamond be 3x, 2x, x and x.
Total weight of diamond = 3x + 2x + x + x = 7x
Cost of the diamond = (7x)3 = 343x3
Cost of first piece = (3x)3 = 27x3
Cost of second piece = (2x)3 = 8x3
Cost of third piece = (x)3 = x3
Cost of fourth piece = (x)3 = x3
Total cost of diamond after weight = 27x3 + 8x3 + x3 + x3
⇒ New cost = 37x3
According to the question,
343x3 – 37x3 = 30600
⇒ 306x3 = 30600
⇒ x3 = 100
So, the original cost of diamond = 343x3 = 343 × 100 = Rs. 34300
∴ The original cost of diamond is R
When the pieces were sold the merchant got 34600 less.
Concept used:
Using the concept simple ratio.
Calculation:
Let the weight of each piece of diamond be 3x, 2x, x and x.
Total weight of diamond = 3x + 2x + x + x = 7x
Cost of the diamond = (7x)3 = 343x3
Cost of first piece = (3x)3 = 27x3
Cost of second piece = (2x)3 = 8x3
Cost of third piece = (x)3 = x3
Cost of fourth piece = (x)3 = x3
Total cost of diamond after weight = 27x3 + 8x3 + x3 + x3
⇒ New cost = 37x3
According to the question,
343x3 – 37x3 = 30600
⇒ 306x3 = 30600
⇒ x3 = 100
So, the original cost of diamond = 343x3 = 343 × 100 = Rs. 34300
∴ The original cost of diamond is R
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