Question

The cost of diamond varies directly as
the square of its weight. Once, this
diamond broke into four pieces with
weights in the ratio 1:2:3:4. When the
pieces were sold, the merchant got Rs.
70,000 less. Find the original price of the
diamond in lacs​

Answer 1

Answer:

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Answer 2

The cost, , varies directly as the weight, , of the diamond

So -----(1) C = W^2

Diamond broke into pieces in the ratio 1:2:3:4

Hence total cost of the pieces will be: ----(2)

(w/10)^2 + (2w/10^2) + (3x/10^2) + (4w/10^2) = 30w^2/100 = 3w^2/10

But we are given that the merchant got $70,000 less from the sale of the 4 pieces.

Hence

w^2 -3w^2 / 10 = 70,000

10w^2 - 3w^2 = 700,000

7w^2 = 700,000

w^2 = 100,00

From (1), we know that , hence the original price of the diamond is $100,000

The answer is A.