The cost of each chair is $800 less than twice the cost of each table.Find the cost of each chair,if the cost of each table is $x
Answers
Answer:
Please mark it brainliest
Step-by-step explanation:
Answer:−
The cost of Table is Rs. 500 and Chair is Rs. 250.
\mathfrak{\large{\underline{\underline{Explanation :-}}}}
Explanation:−
Given :
Cost of table is twice the cost of chair
Both cost together = Rs. 750
To Find :
Cost of table and chair
Solution :
Consider the cost of chair as x
Table's Cost = 2x
★ \boxed{\sf{x+2x=750}}
x+2x=750
\sf{\implies} \: x + 2x = 750⟹x+2x=750
\sf{\implies} \: 3x = 750⟹3x=750
\sf{\implies} \: x = \dfrac{750}{3}⟹x=
3
750
\sf{\implies} \: x = 250⟹x=250
Chair = Rs. 250
\rule{300}{1.5}
★ Value of 2x
\sf{\implies} \: 2 \times 250⟹2×250
\sf{\implies} \: 500⟹500
Table = Rs. 500
\therefore∴ The cost of Table is Rs. 500 and Chair is Rs. 250.
\rule{300}{1.5}
\mathfrak{\large{\underline{\underline{Verification :-}}}}
Verification:−
\sf{\implies} \: 250 + (2 \times 250) = 750⟹250+(2×250)=750
\sf{\implies} \: 250 + 500 = 750⟹250+500=750
\sf{\implies} \: 750 = 750⟹750=750
\therefore∴ The cost of Table is Rs. 500 and Chair is Rs. 250
Step-by-step explanation:
ANSWER
Let cost of one chair be Rs x and cost of one table be Rs y
Now as per the question,
3x+2y=1850 .....(1)
5x+3y=2850 ......(2)
Now mutiplying equation (1) by 5 and equation (2) by 3
15x+10y=9250 .....(3)
15x+9y=8550 ......(4)
Now subtracting equation (4) from equation (3)
⇒y=700
Put this value in eq (1),
⇒3x+2(700)=1850
3x+1400=1850
3x=450
x=150
Now total cost of 1 chair and 1 table = x+y
=150+700=850
So, total cost of 1 chair and 1 table is Rs 850
MARK me as BRAINLIST and FOLLOW me