Question

The cost of eight bananas and 9 guavas is 43rs. the cost of 5 bananas and 7 guavas is 31 rs. The cost of three bananas and two guavas is?​

Answer 1

$\large{\underline{\underline{\mathfrak{\green{\sf{QUESTION:-}}}}}}$.

• The cost of eight bananas and 9 guavas is 43rs. the cost of 5 bananas and 7 guavas is 31 rs. The cost of three bananas and two guavas is?

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$\large{\underline{\underline{\mathfrak{\green{\sf{SULUTION:-}}}}}}$.

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$\large{\underline{\underline{\mathfrak{\sf{Given\:Here:-}}}}}$.

• The cost of eight bananas and 9 guavas is 43rs.

• the cost of 5 bananas and 7 guavas is 31 rs.

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$\large{\underline{\underline{\mathfrak{\sf{Find\:Here:-}}}}}$.

• The cost of three bananas and two guavas is?

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$\large{\underline{\underline{\mathfrak{\sf{EXPLANATION:-}}}}}$.

Let,

• Banana = x

• Guava = y

A/C to question ,

• $\:(8x + 9y)\:=\:43$ ......(1)

• $\:(5x+7y)\:=\:31$.......(2)

Multiply by 5 × (1) - 8 × (2)

We get,

• $\:(40x + 45y \:=\:215$

• $\:(40x+56y)\:=\:248$

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$\implies\:-11y\:=\:-33$

$\implies\:y\:=\frac{\cancel{-33}}{\cancel{-11}}$

$\bold{\boxed{\boxed{\:y\:=\:3}}}$

Keep Value of y in equation (1)

$\implies\:(8x+9\times\:3)\:=\:43$

$\implies\:(8x)\:=\:(43-27)$

$\implies\:x\:=\frac{\cancel{16}}{\cancel{8}}$

$\bold{\boxed{\boxed{\:x\:=\:2}}}$

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Now, we find here ,

• Cost of three banana and two guava

$\implies\:(3x+2y)\:=\:(3\times\:2\:+\:2\times\:3)$

$\implies\:(3x+2y)\:=\:(6+6)$

$\bold{\boxed{\boxed{\:(3x+2y)\:=\:12}}}$

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$\large{\underline{\underline{\mathfrak{\sf{ANSWER:-}}}}}$.

• Cost of two banana and three guava = 12 rupees

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