Math, asked by VishitM, 1 year ago

The cost of enclosing a rectangular garden with a fence all around at the rate of RS 15 per meter is RS 5400. If the length is 100m , find the area of the garden .

Answers

Answered by doraemondorami2
150
The cost for enclosing a rectangular garden with a fence = 5400 RS 
The perimeter of the rectangle = 2(l+b)
Length of the rectangle(l) = 100 m
Rate of fencing per metre = 15 RS
Therefore 2(l+b)*15=5400
100+b = 5400/30 = 180
breadth (b) = 180 - 100 = 80 m .
Area of the rectangle = l*b = 100*80 = 8000 square metres.
Answered by Anonymous
5

Consider ABCD as a rectangular field of measurement 15m × 8m

Length = 15 m

Breadth = 8 m

Here the area = l × b = 15 × 8 = 120 m2

Measurement of tiles = 50 cm × 25 cm

Length = 50 cm = 50/100 = ½ m

Breadth = 25 cm = 25/100 = ¼ m

So the area of one tile = ½ × ¼ = 1/8 m2

No. of required tiles = Area of rectangular field/Area of one tile

Substituting the values

= 120/ (1/8)

By further calculation

= (120 × 8)/ 1

= 960 tiles

Length of carpet = 15 – 1 – 1

= 15 – 2

= 13 m

Breadth of carpet = 8 – 1 – 1

= 8 – 2

= 6 m

Area of carpet = l × b

= 13 × 6

= 78 m2

We know that

Area of floor which is uncovered by carpet = Area of floor – Area of carpet

Substituting the values

= 120 – 78

= 42 m2

Fraction = Area of floor which is uncovered by carpet/ Area of floor

Substituting the values

= 42/120

= 7/20

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