Question

The cost of fencing a rectangular field at 18 per metre is 1980. If the width of the field is
23 m, find its length.​

Answer 1

Answer:

The perimeter of the rectangle field =

$\frac{1980}{18} = 110$

The width of the field =23 m

The width of the field =23 mWe know that

The width of the field =23 mWe know that2(length+width)=110

The width of the field =23 mWe know that2(length+width)=110Therefore,

The width of the field =23 mWe know that2(length+width)=110Therefore,2(length+23)=110

The width of the field =23 mWe know that2(length+width)=110Therefore,2(length+23)=110length+23=55

The width of the field =23 mWe know that2(length+width)=110Therefore,2(length+23)=110length+23=55length=32 m

The width of the field =23 mWe know that2(length+width)=110Therefore,2(length+23)=110length+23=55length=32 mHence, this is the answer.

Step-by-step explanation:

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Answer 2

Answer:

32 m

Step-by-step explanation:

The perimeter of the rectangle field = $\frac{1980}{18}$=110 m

The width of the field =23 m

We know that

2(length+width)=110

Therefore,

2(length+23)=110

length+23=55

length=32 m

Hence, this is the answer.