Question

the cost of fencing a rectangular field at rupees 40 per metre is rupees 3200 .if the length of the field is 24 metre then it's breadth is ​

Answer 1

Question :

the cost of fencing a rectangular field at rupees 40 per metre is rupees 3200 .if the length of the field is 24 metre then it's breadth is ?

Answer :

$\sf\pink{Given:}$

• cost of fencing at the rate of Rs 40 per metre is Rs 3200 .

• length of the rectangular field is 24 m.

$\sf\pink{To\:find:}$

• Breadth of the rectangular field ?

Explanation :

cost of fencing = Rate × Perimeter

$\\ \longrightarrow\sf{ 3200 = 40 × Perimeter}$

$\\ \longrightarrow\sf{ Perimeter = \dfrac{3200}{40}}$

$\\ \longrightarrow\sf{ Perimeter = \dfrac{320}{4}}$

$\\ \longrightarrow\sf{ Perimeter = 80}$

Therefore the perimeter is 80 m.

Perimeter = 2 ( l + b )

$\\ \longrightarrow\sf{80 = 2 ( 24 + b )}$

$\\ \longrightarrow\sf{80 = 48 + 2b }$

$\\ \longrightarrow\sf{80 - 48 = 2b }$

$\\ \longrightarrow\sf{32 = 2b }$

$\\ \longrightarrow\sf{b = \dfrac{32}{2}}$

$\\ \longrightarrow\sf{b = 16}$

Therefore the breadth of the rectangular field is 16 m .

Answer 2

Step-by-step explanation:

Given:

cost of fencing at the rate of Rs 40 per metre is Rs 3200 .

length of the rectangular field is 24 m.

\sf\pink{To\:find:}Tofind:

Breadth of the rectangular field ?

Explanation :

cost of fencing = Rate × Perimeter

\begin{gathered}\\ \longrightarrow\sf{ 3200 = 40 × Perimeter}\end{gathered}

⟶3200=40×Perimeter

\begin{gathered}\\ \longrightarrow\sf{ Perimeter = \dfrac{3200}{40}}\end{gathered}

⟶Perimeter=

40

3200

\begin{gathered}\\ \longrightarrow\sf{ Perimeter = \dfrac{320}{4}}\end{gathered}

⟶Perimeter=

4

320

\begin{gathered}\\ \longrightarrow\sf{ Perimeter = 80}\end{gathered}

⟶Perimeter=80

Therefore the perimeter is 80 m.

Perimeter = 2 ( l + b )

\begin{gathered}\\ \longrightarrow\sf{80 = 2 ( 24 + b )}\end{gathered}

⟶80=2(24+b)

\begin{gathered}\\ \longrightarrow\sf{80 = 48 + 2b }\end{gathered}

⟶80=48+2b

\begin{gathered}\\ \longrightarrow\sf{80 - 48 = 2b }\end{gathered}

⟶80−48=2b

\begin{gathered}\\ \longrightarrow\sf{32 = 2b }\end{gathered}

⟶32=2b

\begin{gathered}\\ \longrightarrow\sf{b = \dfrac{32}{2}}\end{gathered}

⟶b=

2

32

\begin{gathered}\\ \longrightarrow\sf{b = 16}\end{gathered}

⟶b=16

Therefore the breadth of the rectangular field is 16 m .