Question

*The cost of fencing a rectangular garden was ₹64500, at the rate of ₹50 per metre. If the length and breadth of the garden are in the ratio 9:6. What is the area of the garden (in square metres)?*

1️⃣ 1290
2️⃣ 258
3️⃣ 99846
4️⃣ 98846​

Answer 1

99846 is the cost of fencing

Answer 2

$\huge\underbrace \color{aqua}Answer$

$\color{lime} \boxed{ \colorbox{black}{ \sf{(3 )99846 sq m}}}$

$\huge\underbrace \color{violet}Explanation$

☆To find :-

▪︎The area of the rectangular garden .

☆Given:-

▪︎The cost of fencing the garden was Rupees 64500

▪︎Rate of cost = Rupees 50 per metre

▪︎The length and breadth of the garden are in the ratio 9 :6

☆Assuming:-

▪︎Let the length be 9x and 6x

☆Formula:-

• Perimeter od rect. =2(length +breadth)

• Area of rect. = length × breadth

☆Solution:-

▪︎The perimeter of the garden

$- > \frac{cost \: of \: fencing}{rate \: of \: cost}$

$- > \frac{64500}{50} = 1290m$

ATQ

》2(9x+6x)=1290

=>2(15x)=1290

=>30x = 1290

$x = \frac{1290}{30} \\ x = 43$

▪︎Therefore, Length = 9x =9×43=387m

▪︎And ,Breadth =6x =6×43=258m

$\color{lightgreen}length = 387m$

$\color{yellow}breadth = 258m$

▪︎Therefore, area of the garden

$- > 387 \times 258 = 99846 {m}^{2}$

☆ Hence :-

$\underbrace\color{pink}Area =99846 {m}^{2}$

____________________________

Extra information:

• Circumference of circle = 2 pie r

• Hypotenuse ²= Base ²+height ²

• Area of trapezium = 1/2(sum of parallel sides)×height

• Surface area of cuboid = 2 (Length x Breadth + breadth x height + Length x height)

• Lateral Surface area of cuboid = 2 height(length + breadth)

• Volume of the cuboid = (length × breadth × height)

€€________________________€€

hope it helps... :)