the cost of five oranges..
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Let cost of one orange be x and one apple be y
ATQ,
5x+3y=30 .........(i)
2x+4y=26 .........(ii)
multiply 2 in (i) and 5 in (ii) we get
10x+6x=60 ...........(iii)
10x+20y=130 ..........(iv)
sub. (iii) from (iv) we get
0.x+14y=70
y=5
putting y=5 in (ii)
2x+20=26
2x=6
x=3
∴cost of one orange=x=3
cost of one apple=y=5 Ans
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