Question

The cost of flooring a rectangular Hall at rupees 64 per square metre is rupees 2048 if the breadth of the hall in 5 M find.it length. ​

Answer 1

Answer:

6.4 m

Step-by-step explanation:

Cost of flooring = ₹2048

Rate of flooring = ₹64

Hence, area would have been = cost of flooring/rate of flooring

→ area of the floor = 2048/64

→ area of floor = 32 m²

Given that breadth = 5 m

and, we derived that area = 32 m²

But area = length × breadth

→ length × 5 = 32

→ length = 32/5

→ length = 6.4 m

Answer 2

Given :-

The total cost of flooring a rectangular hall = Rs 2048

The cost per m square is Rs 64

So,

Let the area of the floor of the rectangular hall be a m sq.

So,

Total cost,

⇒ a × 64 = 2948

⇒ a = 2048 ÷ 64

⇒ a = 32

Therefore,

The area of the floor of the rectangular hall is 32 m sq.

Now,

To be found:-

The length of the floor

The breadth is given = 5m

We know that,

Area of rectangle = lb unit sq.

[ ∴ In which l is the length and b is the breadth of the rectangle ]

⇒ 32 = l × 5

⇒ 32 ÷ 5 = l

⇒ 6.4 = l

Hence,

the length is 6.4 m

Answer 3

_________________________


$\bold{Given:-}$


Breadth of the floor $= 5\:m$


Total cost of flooring the hall $= Rs.\:2048$


Cost of flooring per square meter $= Rs.\:64$


$\bold{Now,}$


Area of the hall = (Refer this attachment)


$\bold{So,}$


$= \frac{2048}{64} m^{2}$


$= 32\:m^{2}$


$\bold{Now,}$


Breadth = ${5\:m}$


Area = ${32\:m^2}$


$\bold{We\:know\:that:-}$


$Area = Length \times Breadth$


So, by substituting the above values,


$\bold{We\:get,}$


$32\:m ^{2} = Length \times 5\:m$


$\frac{32\:m ^{2} }{5\:m} = Length$


$6.4\:m = Length$


$\bold{Therefore,}$


The length of the hall is $\bold{6.4\:m.}$


_________________________