Question

the cost of fuel for running a bus is proportional to the square of the speed generated in kilometre per hour it costs rupees 48 per hour when the bus is moving at the speed of 20 km per hour what is the most economical speed if the fixed charges are Rs 108 an hour over and above the running charge.(Using differentation)


Please anyone help me

Answer 1

R1 = 48 rs per hour

speed1 = 20km/h

prpositon of first given sum is

R1 : speed1

48:20

24:10

12:5

R2 = 108 rs

S2 = 'x'

108:x = 12:5

108 x 12 =5x

1296 = 5x

5x= 1296

x =1296/5

x= 259.2

Answer 2

Answer:

Step-by-step explanation: