Math, asked by tanishasinha3967, 1 year ago

The cost of harvesting a square field at the of rupees 190 per meter hectar is rupees 2327.5 .find the cost of putting a fence around it at the rate of rupees 7.50 per meter

Answers

Answered by Anonymous
76
 \bf{ \mathsf{\huge{SOLUTION - }}}

 \bf{ \mathsf{Given {\ratio - }}}

 \implies{\bf{ \underline{ \tiny{ \mathsf{ Cost \: of \: \: harvesting \: \: a \: \: Square \: \: field \: at \: the \: of \: rupees \: 190 per meter hectare \: is \: rupees \:  Rs 2327.5  }}}}}

\implies{\bf{ \underline{ \tiny{ \mathsf{ Area \: of \: the \: field = \frac{cost \: of \: the \: fencing \: of \: field \: }{rate \: \: of \: the \: field}}}}}}
\implies{\bf{ \tiny{ \mathsf{ Area \: of \: the \: field = \frac{2327.5}{190} = 12.25hectare}}}}
\implies{\bf{ \tiny{ \fbox{ \bf{ \mathsf{ change \: \: hectares \: \: in \: to \: metre \: square}}}}}}

\implies{\bf{ \tiny{ \mathsf{ Area \: of \: the \: field =12.25 \times 10000 = 122500 \: square \: unit}}}}

\implies{\bf{ \tiny{ \mathsf{ Area \: of \: the \: field = \sqrt{122500} = 350}}}}

\implies{\bf{ \tiny{ \mathsf{ perimeter \: of \: the \: square \: field =4 \times sides}}}}
\implies{\bf{ \tiny{ \mathsf{350 = 4 \times sides}}}}
\implies{\bf{ \tiny{ \mathsf{sides = 87.5}}}}
\implies{\bf{ \tiny{ \mathsf{according \: to \: the \: question \: \: statement - }}}}
\implies{\bf{ \tiny{ \mathsf{required \: cost \: \: will \: be \: = 87.50 \times 7.50}}}}
\implies{\bf{ \tiny{ \mathsf{cost \: of \: fencing \: the \: field = 756.25}}}}
\implies{\bf{ \tiny{ \mathsf{hence \: \: cost \: of \: fencing \: the \: field =Rs. 756.25}}}}

Anonymous: Thanks
Answered by Awesome98
2
CostofharvestingaSquarefieldattheofrupees190permeterhectareisrupeesRs2327.5​

\implies{\bf{ \underline{ \tiny{ \mathsf{ Area \: of \: the \: field = \frac{cost \: of \: the \: fencing \: of \: field \: }{rate \: \: of \: the \: field}}}}}}

Areaofthefield=rateofthefieldcostofthefencingoffield​​
\implies{\bf{ \tiny{ \mathsf{ Area \: of \: the \: field = \frac{2327.5}{190} = 12.25hectare}}}}

Areaofthefield=1902327.5​=12.25hectare 
\implies{\bf{ \tiny{ \fbox{ \bf{ \mathsf{ change \: \: hectares \: \: in \: to \: metre \: square}}}}}}

changehectaresintometresquare​ 

\implies{\bf{ \tiny{ \mathsf{ Area \: of \: the \: field =12.25 \times 10000 = 122500 \: square \: unit}}}}

Areaofthefield=12.25×10000=122500squareunit 

\implies{\bf{ \tiny{ \mathsf{ Area \: of \: the \: field = \sqrt{122500} = 350}}}}⟹Areaofthefield=122500​=350 

\implies{\bf{ \tiny{ \mathsf{ perimeter \: of \: the \: square \: field =4 \times sides}}}}

perimeterofthesquarefield=4×sides 


\implies{\bf{ \tiny{ \mathsf{350 = 4 \times sides}}}}

350=4×sides


\implies{\bf{ \tiny{ \mathsf{sides = 87.5}}}}⟹sides=87.5 <br />\implies{\bf{ \tiny{ \mathsf{according \: to \: the \: question \: \: statement - }}}}

accordingtothequestionstatement− 
\implies{\bf{ \tiny{ \mathsf{required \: cost \: \: will \: be \: = 87.50 \times 7.50}}}}

requiredcostwillbe=87.50×7.50 
\implies{\bf{ \tiny{ \mathsf{cost \: of \: fencing \: the \: field = 756.25}}}}⟹costoffencingthefield=756.25 
\implies{\bf{ \tiny{ \mathsf{hence \: \: cost \: of \: fencing \: the \: field =Rs. 756.25}}}}

hencecostoffencingthefield=Rs.756.25
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