The cost of painting an open underground tank of 3m long, 2m wide and 1.5 m high at Rs 20 per m^2 is ______
I want it with steps, plz^100000
Answers
Answered by
20
Given that
The length of the tank = 3m.
The Breadth of the tank = 2m.
The height of the tank = 1.5m
We know that Area of the surface = 2(bh + lh) + lb
= 2(2 * 1.5 + 3 * 1.5) + 3 * 2
= 2(3 + 4.5) + 6
= 2(7.5) + 6
= 21.
Total area of painting = 21m^2.
Given cost of painting = 20 per m^2
Total cost of painting = 20 * 21
= 420.
Therefore the total cost of painting = 420 rupees.
Hope this helps!
The length of the tank = 3m.
The Breadth of the tank = 2m.
The height of the tank = 1.5m
We know that Area of the surface = 2(bh + lh) + lb
= 2(2 * 1.5 + 3 * 1.5) + 3 * 2
= 2(3 + 4.5) + 6
= 2(7.5) + 6
= 21.
Total area of painting = 21m^2.
Given cost of painting = 20 per m^2
Total cost of painting = 20 * 21
= 420.
Therefore the total cost of painting = 420 rupees.
Hope this helps!
siddhartharao77:
If possible brainliest the effort.
Thanq
I was taking taking out area of 4 walls
No. You should not take that.
yes
thanq for telling
Okk
Hey, total.surface area.is 2(lb+bh+hl)
u have written wrong frnd
No, That's the different formula
Answered by
0
Answer:
420
Step-by-step explanation:
Given that
The length of the tank = 3m.
The Breadth of the tank = 2m.
The height of the tank = 1.5m
We know that Area of the surface = 2(bh + Ih) + lb
+3*1.5) + 3*2
=2(2 * 1.5
4.5) + 6
= 2(3+
= 2(7.5) + 6
= 21.
Total area of painting = 21m^2.
Given cost of painting = 20 per m^2
Total cost of painting = 20 21
= 420.
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