the cost of polishing acircular table top of diameter 2.1 m if the rate of polishing is 10 per m2
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r= d/2
= 2.1/2
r =1.05
area of circular table top = pai r^2
= 22/7×1.05×1.05
=22×0.15×1.05
=3.4650m^2
cost of 1m ^2= 10rs
cost of 3.465m^2 =(3.465×10)rs
= 34.65rs
= 2.1/2
r =1.05
area of circular table top = pai r^2
= 22/7×1.05×1.05
=22×0.15×1.05
=3.4650m^2
cost of 1m ^2= 10rs
cost of 3.465m^2 =(3.465×10)rs
= 34.65rs
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