The cost of polishing the TSA of a solid cylinder at 25 paise per cm^2 is Rs.770. The height of the cylinder is three times its radius. Find the radius and the height of the cylinder.
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Answer:
TSA = 770×100÷25 = 770×4
TSA = 2pi.r^2 +2pi.r.h
h = 3r
TSA = 2.pi.(r^2 + r.3r) = 2.pi.4.r^2 = 770×4
substitute the value of pi, take the square root of r^2, you will get r =5√2•5 and h = 15√2•5 cm
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