the cost of preparing the wall of a room 12 m long at the rate of rupees 1.35 per metre square is rupees 340.20 and the cost of matting the floor at 85 paise per metre square is rupees 91.80 find the height
Answers
Answer:
Length of the room = 12 m.
Cost of matting the floor = ₹ \frac{0.85}{ {m}^{2} }
Cost of preparing the walls = ₹ \frac{1.35}{ {m}^{2} }
Let the length and height of the room be ' b ' m and ' h ' m .
We know that ,
Area \: of \: the \: floor \: = l \times bAreaofthefloor=l×b
= 12m \times bm = 12b \: {m}^{2}=12m×bm=12bm
2
Hence ,
Total cost of matting the Floor = ₹ 0.85 × 12b
= > ₹0.85 \times 12b = ₹91.80=>₹0.85×12b=₹91.80
\: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: 12b = \frac{91.80}{0.85}12b=
0.85
91.80
\: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: b = \frac{108}{12}b=
12
108
\: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: b = 9mb=9m
Breadth of the room , b = 9m
Now ,
Area of walls of the room = 2 ( l + b )× h
=2 ( 12m + 9m ) × h
= 21 × 2 × h
= 42h m^2
cost \: of \: preparing \: the \: walls \: =₹ \frac{1.35}{ {m}^{2} }costofpreparingthewalls=₹
m
2
1.35
Total cost of preparing the walls = ₹ 1.35 × 42h
₹1.35 × 42 h = ₹ 340 × 20
42h = \frac{340.20}{1.35}42h=
1.35
340.20
42h = 25242h=252
h = \frac{252}{42}h=
42
252
h = 6 .
Step-by-step explanation:
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