the cost of producing x items per day is given in rupees asC(x)=2000+100√x.If each item can be sold for Rs.10, determine the breakeven point
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Secondary SchoolMath5 points
The price P per unit at which a company can sell all that it produces is given by the function P(x) = 300 — 4x. The cost function is c(x) = 500 + 28x where x is the number of units produced. Find x so that the profit is maximum.
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Ask for details FollowReport byErpawankumar0007 09.01.2017
is the answer 37
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Me · Beginner
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profswhAmbitious
Total selling price = P.x
= (300 - 4x)x
profit = P*x - C
= (300 - 4x)x - (500 +28x)
for this to be maximum, (300 - 4x)x should be maximum
maximum value of a quadratic equation = -b/2a
= -300/(-2*4)
= 37.5
this can yield two values 37 and 38. you will find that P.x is same for both value
so now C is less for 37
so the answer is 37
Hope its help uh
Ur answer is here
Answer.... =>
1
Secondary SchoolMath5 points
The price P per unit at which a company can sell all that it produces is given by the function P(x) = 300 — 4x. The cost function is c(x) = 500 + 28x where x is the number of units produced. Find x so that the profit is maximum.
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Ask for details FollowReport byErpawankumar0007 09.01.2017
is the answer 37
Log in to add a comment
Answers
Me · Beginner
Know the answer? Add it here!
profswhAmbitious
Total selling price = P.x
= (300 - 4x)x
profit = P*x - C
= (300 - 4x)x - (500 +28x)
for this to be maximum, (300 - 4x)x should be maximum
maximum value of a quadratic equation = -b/2a
= -300/(-2*4)
= 37.5
this can yield two values 37 and 38. you will find that P.x is same for both value
so now C is less for 37
so the answer is 37
Hope its help uh
Answered by
4
Answer:
break even point is 400
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