Question

The cost of production per unit for two products, A and B, are ₹100 and ₹80 respectively. In a week,the total production cost is ₹32000. In the next week, the production cost reduces by 20%, and the total cost of producing the same number of units of each product is ₹25600. Which of these are the equations that can be used to find the number of units of A, x, and the number of units of B, y?​

Answer 1

Answer:

a) 100x + 80x = 32000 and 80x + 64y = 25600

Answer 2

Given Question

The cost of production per unit for two products, A and B, are ₹100 and ₹80 respectively. In a week,the total production cost is ₹32000. In the next week, the production cost reduces by 20%, and the total cost of producing the same number of units of each product is ₹25600. Which of these are the equations that can be used to find the number of units of A, x, and the number of units of B, y?

$\green{\large\underline{\sf{Solution-}}}$

Given that,

➢ Number of units of A produced = x

➢ Number of units of B produced = y

According to first condition

➢ Cost of production per unit of A = ₹ 100

➢ So,Cost of production of x units = ₹ 100x

➢ Cost of production per unit of B = ₹ 80

➢ So, Cost of production of y units = 80y

➢ Total production cost is ₹ 32000

$\red{\rm\implies \:\boxed{\tt{ 100x + 80y = 32000}} - - - (1)}$

According to second condition

As cost is reduced by 20 %, so

➢ Cost of production per unit of A = 100 - 20 = ₹ 80

➢ So,Cost of production of x units = ₹ 80x

➢ Cost of production per unit of B = 80 - 16 = ₹ 64

➢ So, Cost of production of y units = 64y

➢ Total production cost is ₹ 25600

$\red{\rm\implies \:\boxed{\tt{ 80x + 64y = 25600}} - - - (2)}$

So, Option (a) is correct