Question

The cost of the 3D ticket was double the cost of the regular admission, d=2r. The family purchased refreshments and spent a total of $18.50. If the total amount of money spent on tickets and refreshments was $94.50, use an equation to find the cost of one regular admission ticket.

Answer 1

Given :

The cost of the 3 D ticket was double the cost of the regular admission

Total money spend on refreshments = $18.50

The total amount of money spent on tickets and refreshments = $94.50

To Find :

The cost of one regular admission ticket.

Solution :

According to question

The cost of the 3 D ticket = 2 × The cost of the regular admission

∵ Total money spend on refreshments = $18.50

And

The total amount of money spent on tickets and refreshments = $94.50

i.e   total amount of money spent on tickets + money spend on refreshments = $94.50

Or, total amount of money spent on tickets = $94.50 - $18.50

Or, Total amount of money spent on tickets = $76

i.e  The cost of the 3 D ticket + The cost of the regular admission = $76

Again

∵  The cost of the 3 D ticket = 2 × The cost of the regular admission

Or, 2 × cost of the regular admission + cost of the regular admission = $76

Or,  3 cost of the regular admission = $76

Or, cost of the regular admission = $\dfrac{76}{3}$

∴ cost of the regular admission = $25.33

Hence, The cost of one regular admission is $25.33         Answer