Math, asked by jaweditd, 1 year ago

the cost of the marble varies directly with square of its weight.marble is broken into 3 parts whose weights are in the ratio 3:4:5. if marble had been broken into three equal parts by weight then there would have been a further loss of rs.1800.what is the actual cost of the original(or unbroken)marble?

Answers

Answered by knjroopa
10

Answer:

1,29,600

Step-by-step explanation:

Given the cost of the marble varies directly with square of its weight.marble is broken into 3 parts whose weights are in the ratio 3:4:5. if marble had been broken into three equal parts by weight then there would have been a further loss of rs.1800.what is the actual cost of the original(or unbroken)marble?

cost of marble C ∝ W^2

Given weights will be W1 : W2 : W3 = 3 : 4 : 5

Now broken marble parts cost will be (3x)^2 + (4x)^2 + (5x)^2 = 50 x^2

When weights of marble are equal cost will be

            (4x)^2 + (4x)^2 + (4x)^2 = 48x^2

So loss = 50 x ^2 - 48 x^2

    loss = 2x^2

So 2x^2 = 1800

  x^2 = 900

So cost of original marble will be (4x + 4x + 4x)^2

                             = (12 x )^2

                           = 144 x^2

                    = 144 x 900

                    = 1,29,600

So the actual cost of the original marble is Rs 1,29,600

Similar questions