the cost of the painting the outer curved surface of a cylinder at 1.50/cm^2 is rupees 660.if the h of cylinder is 20 then find the CSA of Base of cylinder.
ishu146:
sorry in there 20 place 2 m come
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Answered by
5
CSA=660/1.50=440cm^2
CSA=2πrh=440
therefore,
22/7rh=440/2
r×20=220×7/22. (h=20)
r=10×7/20
r=7/2
area of base= πr×r=22/7×7/2×7/2=77/2=38.5cm^2
CSA=2πrh=440
therefore,
22/7rh=440/2
r×20=220×7/22. (h=20)
r=10×7/20
r=7/2
area of base= πr×r=22/7×7/2×7/2=77/2=38.5cm^2
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2
is it right I am not confirm
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38.5cm^2
yes
i was wrong
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