Question

The cost of turfing a triangular field at rupees 25 per 10m sq is rupees 600.find its altitude if the base is three times the altitude.​

Answer 1

Answer:

The altitude is 12.64 m

Step-by-step explanation:

Let the altitude of triangular field be x

We are given that the base is three times the altitude.

So, Base = 3x

Area of turfing done at Rs.25 = 10 m^210m2

Area of turfing done at Re.1 =\frac{10}{25}2510

Area of turfing done at Rs.600 = \frac{10}{25} \times 600=240 m^22510×600=240m2

Area of triangular field =\frac{1}{2} \times Base \times Height21×Base×Height

So,\frac{1}{2} \times 3x \times x = 24021×3x×x=240

\frac{3}{2}x^2=24023x2=240

x^2=\frac{240 \times 2}{3}x2=3240×2

x=\sqrt{\frac{240 \times 2}{3}}x=3240×2

x=12.64

Hence The altitude is 12.64 m

#Learn more:

The base of triangular field is three times its altitude. if the cost of sowing the field at Rs.58 per hectare is Rs. 783, find its base and altitude

Answer 2

Given :

The cost of turfing a triangular field at rupees 25 per 10m sq is rupees 600.

To find :

Altitude if the base is three times the altitude.

Solution :

The cost of turfing a triangular field at rupees 25 per 10m²

Total area of triangular field

→ 10/25 × 600

→ 6000/25

→ 240 m²

•°• Area of triangular field = 240 m²

• The base is three times the altitude.

Let the altitude be x and base be 3x

According to the formula of area of trianlge

→ ½ × base × height = 240

→ ½ × b × h = 240

→ ½ × 3x × x = 240

→ 3x²/2 = 240

→ 3x² = 2 × 240

→ 3x² = 480

→ x² = 480/3

→ x² = 160

→ x = √160

→ x = ± 12.64 m

Focus Zone = Length never be in negative

•°• Altitude of triangular field = 12.64 m

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