Question

the cost of two banks and three chairs are rupees 9000 the cost of bench is thrice that of a chair find the cost of a bench and a chair​

Answer 1

Answer:

Question : The cost of 2 chairs and 3 tables is Rs.800 and the cost of 4 chairs and 3 tables is Rs.1000. Find the cost of 2 chairs and 2 tables.

Step-by-step explanation:

Answer :

Let the cost of one chair be Rs. x

Let the cost of one chair be Rs. xthe cost of one table be Rs. y

Let the cost of one chair be Rs. xthe cost of one table be Rs. yGiven that:

Let the cost of one chair be Rs. xthe cost of one table be Rs. yGiven that: 2x+3y=800−Eq.(1)

Let the cost of one chair be Rs. xthe cost of one table be Rs. yGiven that: 2x+3y=800−Eq.(1)and 4x+3y=1000−Eq.(2)

Let the cost of one chair be Rs. xthe cost of one table be Rs. yGiven that: 2x+3y=800−Eq.(1)and 4x+3y=1000−Eq.(2)To find: 2x+2y

Let the cost of one chair be Rs. xthe cost of one table be Rs. yGiven that: 2x+3y=800−Eq.(1)and 4x+3y=1000−Eq.(2)To find: 2x+2yNow, first of all calculate the value of x and y

Let the cost of one chair be Rs. xthe cost of one table be Rs. yGiven that: 2x+3y=800−Eq.(1)and 4x+3y=1000−Eq.(2)To find: 2x+2yNow, first of all calculate the value of x and ySubtracting Eq. (2) from Eq. (1) we have

Let the cost of one chair be Rs. xthe cost of one table be Rs. yGiven that: 2x+3y=800−Eq.(1)and 4x+3y=1000−Eq.(2)To find: 2x+2yNow, first of all calculate the value of x and ySubtracting Eq. (2) from Eq. (1) we have(4x−2x)+(3y−3y)=(1000−800)

Let the cost of one chair be Rs. xthe cost of one table be Rs. yGiven that: 2x+3y=800−Eq.(1)and 4x+3y=1000−Eq.(2)To find: 2x+2yNow, first of all calculate the value of x and ySubtracting Eq. (2) from Eq. (1) we have(4x−2x)+(3y−3y)=(1000−800)2x+0=200

Let the cost of one chair be Rs. xthe cost of one table be Rs. yGiven that: 2x+3y=800−Eq.(1)and 4x+3y=1000−Eq.(2)To find: 2x+2yNow, first of all calculate the value of x and ySubtracting Eq. (2) from Eq. (1) we have(4x−2x)+(3y−3y)=(1000−800)2x+0=2002x=200

$x \: = \: \frac{200}{2}$

x=100

x=100Substituting the value of x in Eq. (1)

x=100Substituting the value of x in Eq. (1)2(100)+3y=800

x=100Substituting the value of x in Eq. (1)2(100)+3y=800200+3y=800

x=100Substituting the value of x in Eq. (1)2(100)+3y=800200+3y=8003y=800−200

x=100Substituting the value of x in Eq. (1)2(100)+3y=800200+3y=8003y=800−2003y=600

$y = \frac{600}{3}$

We need to find 2x+2y

We need to find 2x+2ySo substituting the calculated values of x and y we have

We need to find 2x+2ySo substituting the calculated values of x and y we have=2(100)+2(200)

We need to find 2x+2ySo substituting the calculated values of x and y we have=2(100)+2(200)=200+400

We need to find 2x+2ySo substituting the calculated values of x and y we have=2(100)+2(200)=200+400=600

We need to find 2x+2ySo substituting the calculated values of x and y we have=2(100)+2(200)=200+400=600Hence, the cost of two chairs and two tables is Rs.600