The cost of two pizzas and 1 burger is Rs 450. Represent this situation
algebraically and also, draw the graph.
(i) If the cost of one burger is Rs. 50, then what is the cost of one Pizza?
(ii) If the cost of one pizza is Rs. 100, then what is the cost of one burger?
(iii) “ Is the graph of the equation passes through the origin? “. Justify the
your answer.
Answers
Answer:
1 spell to 2 is equal to 15 5 100 degree what is justify cost of phone Pizza is rupees hundred burger is 15
Step-by-step explanation:
[ 1³ = 1
2³ = 8
3³ = 27
4³ = 64
5³ = 125
6³ = 216
7³ = 343
8³ = 512
9³ = 729
10³ = 1000
11³ = 1331
12³ = 1728
13³ = 2194
14³ = 2744
15³ = 3375
16³ = 4096
17³ = 4913
18³ = 5832
19³ = 6859
20³ = 8000
21³ = 9261
22³ = 10648
23³ = 12167
24³ = 13824
25³ = 15625
26³ = 17576
27³ = 19683
28³ = 21952
29³ = 24389
30³ = 27000
31³ = 29791
32³ = 32768
33³ = 35937
34³ = 39304
35³ = 42875
36³ = 46656
37³ = 50653
38³ = 54872
39³ = 59319
40³ = 64000
41³ = 68921
42³ = 74088
43³ = 79507
44³ = 85184
45³ = 91125
46³ = 97336
47³ = 103823
48³ = 110592
49³ = 117649
50³ = 125000
51³ = 132651
52³ = 140608
53³ = 148877
54³ = 157464
55³ = 166375
56³ = 175616
57³ = 185193
58³ = 195112
59³ = 205379
60³ = 216000
61³ = 226981
62³ = 238328
63³ = 250047
64³ = 262144
65³ = 274625
66³ = 287496
67³ = 300763
68³ = 314432
69³ = 328509
70³ = 343000
71³ = 357911
72³ = 373248
73³ = 389017
74³ = 405224
75³ = 421875
76³ = 438976
77³ = 456533
78³ = 474552
79³ = 493039
80³ = 512000
81³ = 531441
82³ = 551368
83³ = 571787
84³ = 592704
85³ = 614125
86³ = 636056
87³ = 658503
88³ = 681472
89³ = 704969
90³ = 729000
91³ = 753571
92³ = 778688
93³ = 804357
94³ = 830584
95³ = 857375
96³ = 884736
97³ = 912673
98³ = 941192
99³ = 970299
100³ = 1000000