the cost of two tables and three chairs is 1800. if the table costs 30 more than a chair, find the price of each
Answers
Answer:
2 tables +3 chairs =1800
table costs 30 mare than chair , that is -2 tables costs =30×2 =60
that's why 1800 -60= 1740
1740÷5(3 chairs +2 tables {cost of table -60} )
= 348
cost of 1 chair =348
cost of 3 chairs = 348 ×3=1044
1800-1044=756
=756 is the cost of 2 tables
cost of 1 table is = 378
cost of 1 table =378 &cost of 1 chair = 348
Answer:
The cost of one chair =348
The cost of three chairs =3x=3(348) =1044
The cost of one table =x+30
And the cost of two tables =2(x+30) =2(348+30)
=2(378) =756
Step-by-step explanation:
let the cost of chair be 'x'
and let the cost of table be 'x+30'
3x+2(x+30) =1800
3x+2x+60=1800
5x=1800-60
5x=1740
x=1740/5
x=348
Therefore, the cost of one chair =348
The cost of three chairs =3x=3(348) =1044
The cost of one table =x+30
And the cost of two tables =2(x+30) =2(348+30)
=2(378) =756