the cost of two tables and three chairs is $ 704.
if the table costs $40 more than the chair , find the cost of the table and chair ..
PLS ANSWER...BEST ANSWER WILL BE MARKED AS BRAINLIEST.
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Answer:
let the cost of one table be X and cost of one chair be y.
2x+ 3y=704$-(I)
now, x-y=40$-(ii)
solve both the equations(I) and (ii),
u will get ,
5y=624$
y=124.8$
X=124.8+40=164.8$
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