The cost of two tables and three chairs is $705. If the table costs $40 more than the chair, find the cost of the table and the chair.
Answers
Answer:
hiii
your answer is here !
Step-by-step explanation:
The table cost $ 40 more than the chair.
Let us assume the cost of the chair to be x.
Then the cost of the table = $ 40 + x
The cost of 3 chairs = 3 × x = 3x and the cost of 2 tables 2(40 + x)
Total cost of 2 tables and 3 chairs = $705
Therefore, 2(40 + x) + 3x = 705
80 + 2x + 3x = 705
80 + 5x = 705
5x = 705 - 80
5x = 625/5
x = 125 and 40 + x = 40 + 125 = 165
Therefore, the cost of each chair is $125 and that of each table is $165.
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Answer:
Hey mate here is your answer....
two tables + three chair = ₹705
table cost = ₹40 more than chair
let the cost of a chair be x
a table cost = x + 40
so, 2 (x + 40) + 3x = 705
2x + 80 + 3x = 705
5x + 80 =705
5x = 705 - 80
5x = 625
x = 625/5
x = 125
cost of table = 125 + 40 = ₹165
cost of chair = ₹125
hope it's helpful for you....
thanks