The cost of two tables and three chairs is $705. If the table costs $40 more than the chair, find the cost of the table and the chair.
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Question - The cost of two tables and three chairs is $705. If the table costs $40 more than the chair, find the cost of the table and the chair.
Answer -
The table cost $ 40 more than the chair.
Let us assume the cost of the chair to be x.
Then the cost of the table = $ 40 + x
The cost of 3 chairs = 3 × x = 3x and the cost of 2 tables 2(40 + x)
Total cost of 2 tables and 3 chairs = $705
Therefore, 2(40 + x) + 3x = 705
80 + 2x + 3x = 705
80 + 5x = 705
5x = 705 - 80
5x = 625/5
x = 125 and 40 + x = 40 + 125 = 165
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