The cost of two tables and three chairs is ₹7050. If the table costs ₹400 more than the chair, find the cost of the table and the chair.
Answers
Answer:
Let the cost of the chair to be
x
.
Then, the cost of the table = ₹
40
+
x
Cost of 3 chairs =
3
x
.
Cost of 2 tables =
2
(
40
+
x
)
Total cost of 2 tables and 3 chairs = ₹ 705
∴
2
(
40
+
x
)
+
3
x
=
705
⇒
80
+
2
x
+
3
x
=
705
⇒
80
+
5
x
=
705
⇒
5
x
=
705
−
80
⇒
5
x
=
625
⇒
x
=
125
Cost of table
=
40
+
x
=
40
+
125
=
165
∴
The cost of table is ₹ 165.
Answer:
the cost of table is 1650
the cost of chair is 1250
Step-by-step explanation:
cost of 2 tables and 3 chairs = ₹7050
let table be x and chair be y
therefore, 2x + 3y = ₹7050
table costs ₹400 more than the chair
therefore, x = (₹400+y)
Therefore, 2(400+y) + 3y = 7050
=800 + 2y + 3y = 7050
therefore, 5y = 7050 - 800 = 6250
5y = 6250
y = 6250 / 5
y = 1250
Therefore cost of one chair = 1250
cost of one table = 1250 + 400 = 1650
Just to cross check...
2x1650 + 3x1250= 7050