Question

the cost of two tables and three chairs is rm705 .if the table cost rm40 more than the chair ,find the cost of the table and the chair.

Answer 1

Answer:

Cost of table = 165

Cost of chair = 125

Step-by-step explanation:

Let, cost of 1 table = x

cost of 1 chair = y

According to question,

2x + 3y = 705 (i)

Also, table cost 40 more than that of chair , So

x = y + 40 (ii)

Putting value of x in (i)

2(y + 40) + 3y =705

2y + 80 +3y = 705

80 +5y = 705

5y = 705 - 80

5y = 625

y = 625 / 5

y = 125

Cost of chair = 125

Also, putting value of y in (ii)

x = 125 + 40

x = 165

So, Cost of table = 165

Cost of chair = 125