the cost of two water bottles and three peelers is rs 1400.if the cost of a peeler is rs50 more than that of a water bottle ,find their costs
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Answered by
5
Answer:
Let the cost of 1 water bottle be x.
Cost of 1 peeler = x+50
According to Question,
2x + 3(x+50) = Rs.1400
=> 2x + 3x + 150 = 1400
=> 5x = 1400 - 150
=> 5x = 1250
=> x = 1250/5
=> x = 250
Hence, the cost of water bottle is Rs.250.
Cost of peeler = Rs.(250+50) = Rs.300
Answered by
0
Answer:
2x+3(x+50)=1400
2X + 3X + 150=1400
5x=1400-150
5x=1250
X=1250/5=250
water bottle=250 Rs
peeler= X+50=250+50=300 Rs
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