Question

The cost of white washing at wall of a room at rupees 1.20 per sqm is rupees rupees 88. Find the highest of the room if it is 6m long and 5m wide

Answer 1

Answer:

h= 3.3m

Step-by-step explanation:

rupees of 1 sqm= 1.20rs

total rupees for whole area =88rs

Therefore, total area= 88/1.20=220/3=73.33 sqm

Given,

Room length, l=6m

Room width ,b=5m

Total surface area= 2h*(l+b) =73.33

2h*(6+5)=73.33

h*11*2 =73.33

h= 73.33/2*11= 73.33/22= 3.3m

Answer 2

Given,

The cost of whitewashing the walls of a room at Rs. 1.20 per m^2 is = Rs. 88

Length of the walls of the room = 6 m

The breadth of the walls of the room = 5 m

To find,

The height of the room.

Solution,

We can simply solve this mathematical problem using the following process:

Let us assume that the height of the room is x m.

Mathematically,

The lateral surface area of a cuboid= 2(height of the room)(length + breadth){Statement-1}

Now, according to the question;

The total cost of whitewashing the walls of the room = Rs. 88

The cost of whitewashing 1 m^2 area of the walls = Rs. 1.20

So, the total area of all the walls

= (total cost of whitewashing the walls of the room)/(cost of whitewashing 1 m^2 area of the walls)

= (Rs. 88)/(Rs. 1.20)

= 73.3 m^2

Now, according to the question;

The total area of all the walls = 73.3 m^2

=> 2(height of the room)(length + breadth) = 73.3 m^2

{according to statement-1}

=> 2(x m)(6 m + 5 m) = 73.3 m^2

=> 2(x m)(11 m) = 73.3 m^2

=> x = (73.3)/(2×11) = (73.3)/(22) = 3.33

=> height of the room = 3.33 m

Hence, the height of the room is equal to 3.33 m.