Question

the cost of(x-5) apples is rs.(x2-9x+20).what is the cost of each apple. in x2 2 is square

Answer 1

cost of (x-5) apples = (x²-9x+20),

then

cost of each apple =(x²-9x+20)/(x-5),

=[(x-5)(x-4)]/(x-5),

=₹(x-4)

Answer 2

Given - Cost of (x-5) apples

Find - Cost of 1 apple

Solution - The cost of each apple is Rupees (x-4).

The given problem can be solved through the unitary method.

The cost of (x-5) apples = x² - 9x + 20

So, the cost of each apple = (x² - 9x + 20)/(x-5)

Taking factors of equation (x² - 9x + 20)

Factors = (x - 5) (x - 4)

Now, the cost of each apple = (x - 5) (x - 4)/(x - 5)

Cancelling (x - 5) as it is present in both numerator and denominator.

So, the cost of each apple is Rupees (x - 4).