the cost of1 pencil3eraser is rs 10 and the cost of 4pencil 6 eraser is rs .28 find out cost of 5 pencil 4 eraser
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Cost of one pencil+3eraser=10
cost of 4 pencil+6eraser=28
so,to find the cost of 5pencil and 4 eraser, we should find the cost of one pecil and one eraser.
let the cost of one pencil be x and cost of one eraser be y.
1st case:
x+3y=10(eq1)
2nd case:
4x+6y=28(eq2)
so by elimination method,
4x+12y=40( multplying eq 1 with 4)
4x+6y =28
6y=12
ie,y=2.
so,cost of eraser,y=2.
putting value of y in eq 2 we get,
x+3*2=10
x+6=10
x=10-6
=4.
cost of one pencil=4.
therefore cost of 5 pencil +4eraser
=5*4+4*2
=20+8
=28.
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