the cost painting the total outside surface of a closed cylindrical oil tank at 60paise per sq dm is 237.60 the height of the tank is 6times the radius of the base of the tank find its volume
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Answered by
195
let the radius = r dm
then height = 6r dm
volume of cylinder= π r2 h
= π r2 x 6 r
the cost of painting the cylinder 60 paise per dm2 is given by 237.60
i.e. volume x 0.6 = 237.60
volume= 237.60/0.6
= 396 dm2
_____________________________________________-thanks______
then height = 6r dm
volume of cylinder= π r2 h
= π r2 x 6 r
the cost of painting the cylinder 60 paise per dm2 is given by 237.60
i.e. volume x 0.6 = 237.60
volume= 237.60/0.6
= 396 dm2
_____________________________________________-thanks______
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21
Answer:
Step-by-step explanation:
then height = 6r dm
the cost of painting the cylinder 60 paise per dm2 is given by 237.60
therefore , volume x 0.6 = 237.60
volume= 237.60/0.6
= 396 dm2
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