The cost per km of an electrical
Cable
is given by c. 120/x + 6oox
Where x is the cross section
Sqm..
Find cross section for
Which cost is least
The least cost per km
Answers
Given : The cost per km of an electrical Cable is given by c. 120/x + 6oox
x is the cross section Sqm..
To Find : cross section for Which cost is least
The least cost per km
Solution:
C = 120/x + 600x
dC/dx = -120/x² + 600
dC/dx = 0
=> -120/x² + 600 = 0
=> 120/x² = 600
=> x² = 1/5
=> x = 1/√5
dC/dx = -120/x² + 600
=> d²C/dx² = 240/x³ > 0
Hence for x = 1/√5 cost is minimum
cross section for Which cost is least is √5 m²
C = 120/(1/√5) + 600*1/√5
=> C = 120√5 + 120√5
=> C = 240√5
=> C = 536.66 Per km
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