Question

the cost price of 12 oranges is equal to the selling price of 15 oranges find the loss percent​

Answer 1

Solution :—

.......................................

Let the cost price of each orange be ₹ 1.

According to question,

CP of 15 oranges = ₹ 15

SP of 15 oranges = CP of 12 oranges = ₹ 12

Thus, CP = ₹ 15 & SP = ₹ 12

Since CP > SP , there is a loss

Loss = CP - SP

= ₹ (15 - 12)

= ₹ 3 

•°• Required loss percent

\begin{lgathered}\bold{ = (\frac{Loss}{CP} \times 100)\%} \\ \\ = \bold{(\frac{3}{15} \times 100)\%} \\ \\ \bold{= 20\%}\end{lgathered}=(CPLoss×100)%=(153×100)%=20% 

Answer 2

Answer:

$\bold{{Question}}$

The cost price of 12 oranges is equal to the selling price of 15 oranges find the loss percent.

$\color{blue}{Answer}$

Let the C.P of of 12 oranges be Rs x

Therefore, C.P of 1 orange =

$\frac{x}{12}$

SP of 15 oranges equals to x

SP of one arrange equals to

$\frac{x}{15}$

loss = CP - SP

$= \frac{x}{12} - \frac{x}{15} \\ = \: \frac{5x - 4x}{60} = \frac{x}{60}$

Loss % = x by 60 by x into 100

= x by 60 into x into 100

=5/3=

$1 \ \frac{2}{3}$

Answer.

Hope it helps.