Math, asked by shubhamcai845449, 11 months ago

The cost price of a mobile phone is 400 less than that of a notebook. The mobile phone is sold at 20% profit and the notebook is sold at 30% loss. The selling price of notebook and mobile phone are in the ratio of 105:172. If the notebook is sold at 10% loss what would be the selling price of notebo

Answers

Answered by ashmill
1

Answer:

8100

Step-by-step explanation:

Take the C.P. Of notebook as x and mobile as (x-400) and then solve

Attachments:
Answered by NysaCious
2

Answer:

Selling price of notebook 8100

Step-by-step explanation:

Let cost price of notebook be X

and cost price of mobile phone be (X-400)

So, selling price of notebook at 30% loss = 70X/100

= 7X/100

Selling price of mobile phone at 20% profit = 120(X-400)/100

= (6X-2400)/5

So, (7X/10) : (6X-2400)/5 = 105:172

or, (7X/10)/(6X-2400)/5 = 105/172

or, (7X/10) × 5/(6X-2400) = 105/172

or, 7X/(12X-4800) = 105/172

or, 1204X = 1260X - 504000

or, 1260X - 1204X = 504000

or, 56X = 504000

or, X = 9000

So, cost price of notebook = 9000

Hence, selling price of notebook at 10% loss = (90×9000)/100 = 8100

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