The cost price of a pen is Rs x and that of a pencil is Rs y . By selling the pen at a profit of 20% and pencil at a profit of 30% , the shopkeeper made total profit of Rs 5 . Frame a linear equation satisfying the condition *
a) 30x +20y =5
b) 2x +3y =50
c)3x +2y = 50
d)20x + 30y = 5
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Answer:
Correct option is
C
Solution:-
Let the cost of pen and pencil be x and y
cost of 2 pens and one pencil is Rs. 35 (Given)
∴ 2x+y=35 ⟶eq
n
(i)
cost of 3 pens and 4 pencils is Rs. 65
∴ 3x+4y=65 ⟶eq
n
(ii)
Multiplying eq
n
(i) by 4, we get
8x+4y=140 ⟶eq
n
(iii)
Subtracting eq
n
(ii) from (iii), we have
8x+4y−3x−4y=140−65
⇒ 5x=75
Hence, the cost of 1 pen
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