Math, asked by shourya7261, 17 days ago

The cost price of an article is 30 percent less
than its selling price. Find, th.e profit or the
loss as percent.​

Answers

Answered by AnjanaUmmareddy
1

Answer:

given, c.p.=

given, c.p.= 100

given, c.p.= 10070

given, c.p.= 10070

given, c.p.= 10070 ×s.p.=0.7s.p.

given, c.p.= 10070 ×s.p.=0.7s.p.since s.p. > c.p, there is a profit

given, c.p.= 10070 ×s.p.=0.7s.p.since s.p. > c.p, there is a profit profit % =

given, c.p.= 10070 ×s.p.=0.7s.p.since s.p. > c.p, there is a profit profit % = c.p

given, c.p.= 10070 ×s.p.=0.7s.p.since s.p. > c.p, there is a profit profit % = c.ps.p.−c.p.

given, c.p.= 10070 ×s.p.=0.7s.p.since s.p. > c.p, there is a profit profit % = c.ps.p.−c.p.

given, c.p.= 10070 ×s.p.=0.7s.p.since s.p. > c.p, there is a profit profit % = c.ps.p.−c.p. ×100=

given, c.p.= 10070 ×s.p.=0.7s.p.since s.p. > c.p, there is a profit profit % = c.ps.p.−c.p. ×100= 0.7c.p.

given, c.p.= 10070 ×s.p.=0.7s.p.since s.p. > c.p, there is a profit profit % = c.ps.p.−c.p. ×100= 0.7c.p.s.p−0.7s.p.

given, c.p.= 10070 ×s.p.=0.7s.p.since s.p. > c.p, there is a profit profit % = c.ps.p.−c.p. ×100= 0.7c.p.s.p−0.7s.p.

given, c.p.= 10070 ×s.p.=0.7s.p.since s.p. > c.p, there is a profit profit % = c.ps.p.−c.p. ×100= 0.7c.p.s.p−0.7s.p. ×100=42

given, c.p.= 10070 ×s.p.=0.7s.p.since s.p. > c.p, there is a profit profit % = c.ps.p.−c.p. ×100= 0.7c.p.s.p−0.7s.p. ×100=42 7

given, c.p.= 10070 ×s.p.=0.7s.p.since s.p. > c.p, there is a profit profit % = c.ps.p.−c.p. ×100= 0.7c.p.s.p−0.7s.p. ×100=42 76

given, c.p.= 10070 ×s.p.=0.7s.p.since s.p. > c.p, there is a profit profit % = c.ps.p.−c.p. ×100= 0.7c.p.s.p−0.7s.p. ×100=42 76

given, c.p.= 10070 ×s.p.=0.7s.p.since s.p. > c.p, there is a profit profit % = c.ps.p.−c.p. ×100= 0.7c.p.s.p−0.7s.p. ×100=42 76 %

Answered by devkumarip9
2

Answer:

the profit per cent is 300/7

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