Question

The cost price of article A is double than that of article B and a shopkeeper marks up both the articles 20% more than the cost price. If at the time of sale, the shopkeeper gave Rs. 9 discount on the total and earns 17% profit on the total, find the cost price of article A.

Answer 1

Answer:

Rs 200

Step-by-step explanation:

let the cost price of article B be denoted as $x$

then that of article A is $2x$

If shopkeeper marks up both the articles 20% more than the cost price, then the marked price of A is;

$\frac{100+20}{100}*2x=2.4x$

and that of B is

$\frac{100+20}{100}*x=1.2x$

The total price of A and B is;

$2.4x+1.2x=3.6x$

The total cost  of A and B is

$x+2x=3x$

when the shopkeeper gave Rs. 9 discount on the total , he/she sold at

3.6x-9

If this amount is equal to 117% of the cost price, then, the cost price can be computed as;

if 117%= 3.6x-9

100%=??

$cost=\frac{3.6x-9}{117} *100\\=\frac{3.6x-9}{1.17}$

Equating this to the initial cost price we get;

$3x=\frac{3.6x-9}{1.17}\\3.51x=3.6x-9\\3.6x-3.51x=9\\0.09x=9\\x=100$

Cost price of article A is 2x= 2*100= Rs 200