Question

The cost price of two beds are equal. One bed is sold at a profit of 25% and the other one for 4212 less
than the first one. If the overall profit earned after selling both the beds is 12%, what is the cost price of each
bed?​

Answer 1

Answer:

16200

Step-by-step explanation:

Let the CP be 100 for each bed

Total CP=200

Sp of one bed=125

Total SP=112%of 200=224

SP of another bed=224-125=99

Diff between SP=125-99

=26

26=4212

100=16200

Answer 2

Answer:

Step-by-step explanation:

Given:-    Let cost price of each bed be Rs. x

               One bed is sold for a 25% profit,

               and the second one is sold for 4212 less than the first.

               After selling both beds, the overall profit is 12%.

To Find:-   Cost price of each bed.

Solution:-   Selling Price:-    $\frac{100+(P or L)}{100}$$*C.P$

                Therefore,

                selling price of bed 1 is (SP1) =  $\frac{100+25}{100} *x$

                and selling price of bed 2 is (SP2)=  $(\frac{100+25}{100}) *x-4214$

                cost price of two beds are equal therefore,

                cost price of 2 bed will be  $x+x=2x$

                the total profit of selling 2 beds is 12% then,

                   $(\frac{100+12}{100} )*2x$

               ∴ SP = SP1 +SP2

                  $(\frac{100+12}{100}) *2x=( \frac{100+25}{100} )2x + (\frac{100+25}{100} )2x-4212$

                  $\frac{112}{100} *2x= \frac{125}{100} x + \frac{125}{100} x-4212$

                  $\frac{56}{25}x= \frac{5x+5x}{4} -4212$

                  $\frac{14x}{25}= 10x-4212$

                  $14x=25(10x-4212)$

                  $14x=250x-105300$

                  $14x-250x=105300$

                  $236x=105300$

                  $x=\frac{105300}{236}$

                  $x=446.186$

Answer:-  ∴ The cost price of each bed is Rs. 446.

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