Question

the cost price of two houses for rs3,60,000.he sells one house at a profit of 15% and the other at a loss of 10% if there no gain or loss in the whole transaction,find the cost price of each house​

Answer 1

Answer:

here,

let,

cp of first house =x

cp of second house=360000-x

in first house

profit% = 15%

(sp1 )= cp + p% of cp

(sp1) =x+ 15/100 * x

(sp1)=115x/100

Step-by-step explanation:

in second house

loss = 10%

(sp2) = cp - l% of cp

(sp2) = (360000-x) - 10/100 * (360000-x)

(sp2) = 90(360000-x)/100

      (sp1) = (sp2)

or, 115x/100 = 90(360000-x)/100

or, 115x= 90(360000-x)

or, 115x = 32400000-90x

or, 205x = 32400000

or, x = 158048.78

hence, first house cost price is Rs. 158048.78 and second house cost is Rs. (360000-158048.78)=  Rs.201951.22

   i hope this is useful for you