the cost price of two watches taken together is rupees 840 if by selling one at a profit of 16% and other at a loss of 12% there is no gain or loss in whole transaction then find the CP of each watch
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Answered by
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HEy!
Let the CP of watch 1 = Rs x.
CP of 2nd watch = 840-x
SP of 1st watch = 116x/100 [16% profit]
SP of 2nd watch= 88(840-x)/100 [12% loss]
No loss/gain
=> 840 = 116x/100 + 88(840-x)/100
=> 840×100= 116x - 88x + 840×88
=> 84000 = 28x+73920
=> 28x= 84000-73920
=> 28x=10080
=> x=10080/28
=> x=360
CP of 1st watch = 360
CP of 2nd watch= 840-x
= 840-360
=480
HOPE IT HELPS :)))
SheetalSoni:
it is right answer
Answered by
0
Explanation:
CP of one watch = x
CP of second watch=(840-x)
SP of first watch= 116x/100
SP of second watch=88/100*(840-x)
So,
116x/100=88/100*(840-x)
1st watch=116x=88×840-88x
204 = 88×840
x=360
each watch=840 -360 =480
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