Question

.The CostPrice of B is 60% more than A. A was sold at 60% profit and B was sold at 20% loss. If the difference between their Selling Price is R.32/-, find the cost price ofB

Answer 1

Answer:

the cost price of B is 40

Step-by-step explanation:

let us take CP of A = 100%

Cp of B = 160

SP of A= 160

SP of B= 80

SP of A - SP of B=32

80% =32

80/100=32

CP of B =3200/80= 40

Answer 2

Answer:

CP of $B$ is $160 Rs.$

Step-by-step explanation:

Given:

CP of $B$ is $60$% more than $A.$ $A$ was sold at $60$% profit and $B$ was sold at $20$% loss. Difference between their Selling Price is $Rs. 32$/-.

Find: The CP of $B.$

Solution:

According to the question,

Let the CP of $A$ is $100x$

CP of $B$ is $160x$

Now, SP of $A$ is $160x$

SP of $B$ is $20$% loss

So, $160-32$

$=128x$

Now, difference of there SP is

SP of $A-$ SP of $B=Rs 32$

$160x-128x=Rs32$

$32x=Rs32$

$x=1Rs$

So, CP of B is $160x$

$=160x Rs$

Hence, the CP of $B$ is $160Rs$

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