Question

. The Coulomb force between two point charges separated by a fixed distance changes from F1 to F2
when the , medium separating the charges is changed from air to glass. Then​

Answer 1

Answer:

Step 1: Initial Force

Initially, the force between charges say q

1

and q

2

seperated with distance r is :

F=

4πϵ

0

1

r

2

q

1

q

2

Step 2: New force calculation

When the charge is doubled and the distance between charges is also doubled,

i.e q

1

′

=2q

1

,q

2

′

=2q

2

,r

′

=2r

The new force will be :

F

′

=

4πϵ

0

1

r

′2

q

1

′

q

2

′

F

′

=

4πϵ

0

1

(2r)

2

(2q

1

)(2q

2

)

=

4πϵ

0

1

r

2

q

1

q

2

=F