Question

The coulombs required for the oxidation of two mole of h2o to o2 are

Answer 1

1 mol of H2O  will give one atom of O Charge on O = – 2Electricity required         =n F= 2 × 96487 Coulombs= 192974 Coulombs= 1.93 × 105 Coulombs

Answer 2

 2H2O→4H+O2+4e− Q=4F =4×96500Cmol−1 =38600cmol−1 (b) Zn is oxidized and Ag2O is reduced to Ag E0cell=E0Ag+/Ag−E0zn2+/zn =[0.344−(−0.76)V]V =1.104V AG0=−nFE0cell =−2×96500cmol−1×1.10V =−213×105Jmol−1